(r-(6)/(r^(2)-1))/((1)/(r-3))

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Solution for (r-(6)/(r^(2)-1))/((1)/(r-3)) equation:


D( r )

r^2-1 = 0

1/(r-3) = 0

r-3 = 0

r^2-1 = 0

r^2-1 = 0

1*r^2 = 1 // : 1

r^2 = 1

r^2 = 1 // ^ 1/2

abs(r) = 1

r = 1 or r = -1

1/(r-3) = 0

1/(r-3) = 0

1 = 0

r belongs to the empty set

r-3 = 0

r-3 = 0

r-3 = 0 // + 3

r = 3

r in (-oo:-1) U (-1:1) U (1:3) U (3:+oo)

(r-(6/(r^2-1)))/(1/(r-3)) = 0

(r-6*(r^2-1)^-1)/(1/(r-3)) = 0

((r-3)*(r-6/(r^2-1)))/1 = 0

r-6/(r^2-1) = 0

(r*(r^2-1))/(r^2-1)-6/(r^2-1) = 0

r*(r^2-1)-6 = 0

r^3-r-6 = 0

r^3-r-6 = 0

r^3-r-6 = 0

{ 1, -1, 2, -2, 3, -3, 6, -6 }

1

r = 1

r^3-r-6 = -6

1

-1

r = -1

r^3-r-6 = -6

-1

2

r = 2

r^3-r-6 = 0

2

r-2

r^2+2*r+3

r^3-r-6

r-2

2*r^2-r^3

2*r^2-r-6

4*r-2*r^2

3*r-6

6-3*r

0

r^2+2*r+3 = 0

DELTA = 2^2-(1*3*4)

DELTA = -8

DELTA < 0

r in { 2}

r-2 = 0

(r-2)/(r^2-1) = 0

(r-2)/(r^2-1) = 0 // * r^2-1

r-2 = 0

((r-3)*(r-2))/1 = 0

( r-2 )

r-2 = 0 // + 2

r = 2

( r-3 )

r-3 = 0 // + 3

r = 3

r in { 3}

r = 2

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